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x^2-0.1x-0.34=0
a = 1; b = -0.1; c = -0.34;
Δ = b2-4ac
Δ = -0.12-4·1·(-0.34)
Δ = 1.37
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.1)-\sqrt{1.37}}{2*1}=\frac{0.1-\sqrt{1.37}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.1)+\sqrt{1.37}}{2*1}=\frac{0.1+\sqrt{1.37}}{2} $
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